To find fisrt and second maximum number using pointers in c++

// max.cpp : Defines the entry point for the console application.
//Finds second maximum number in the array.

#include "stdafx.h"
#include<iostream>
using namespace std;
//Define a function max which gives maximun and second maxium number.
//Pass two int variables by-refernce and an array.

void max(int [],int *,int *);
int _tmain(int argc, _TCHAR* argv[])
{
      //Define three int variables and an array of your required size.
int max1,max2,i,a[10]; 
      cout<<"enter array elements"<<endl; //Input value of array elements.
      for(i=0;i<10;i++)             //Loop for input.
      {
      cin>>a[i];
      }
      max(a,&max1,&max2);                 //Call the function.
                                   

//These lines will execute after function execution.

      cout<<"\nMaximum number is"<<max1<<endl;
      cout<<"\n 2nd maximum number is"<<max2<<endl;
      return 0;
}
//Function will receive address of variables and array.

 void max(int b[10],int *m1,int *m2)           
{    
int j,min=b[0];//Define an int min required to find 2nd maximum number.
      *m1=b[0];
     
      for(j=0;j<10;j++)             //First find maximum number.             
      {
      if(b[j]>*m1)
      *m1=b[j];                     //Maximum number is in *m1.
      if(b[j]<min)                  //Find minimum number
      min=b[j];
      }
     
     
      cout<<"\nMinimum number is"<<min<<endl;
      *m2=min;
      for(j=0;j<10;j++) //Now here the logic for second maximum number.
      {
           
//If b[J] is greatar than *m2 and b[j] is less than *m1 which is
//maximum number then assign *m2 the value of element of array pointing
//currently.
      if(b[j]>*m2 && b[j]<*m1)           
      {
      *m2=b[j];
     
      }
      }
     

 }


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